Is time travel possible? 7 best steps

time travel

Is time travel possible?For a fixed date & fixed time can same person be at 3 different locations??Let us discover with 7 best steps.

Is time travel possible?Let us discover with 7 best steps

time travel

Here are crazy questions.

1. For a fixed date & fixed time can same person be at 3 different locations??can time travel possible?

2. Can a person go back in time?? Can a person go ahead of time??

3.Is it possible for the same person who was in London can catch the airbus/flight which was scheduled at same time, same date at three different locations say at Hyderabad,Dubai,Canada and can go back to Home(i.e London) and travel time or journey time between to all those locations should be “ZERO”??

Come on let us discover weather time travel is possible or not.

UNIVERSAL TIME COORDINATED(UTC) FOR LOCATIONS

The person who was in London should catch the flight/airbus at Hyderabad , Dubai , Canada which are  scheduled in all locations at same date and same time.i.e. :Time 05:30 early morning , Date – 10.10.2020.

Is it possible ?? Let us discuss.

As per Universal time coordinated (UTC),the above schedule time in London is UTC+1 ………………………….Step-1

for Hyderabad is UTC+5:30 …………..Step-2

for Dubai is UTC+4…………………………Step-3

For Canada is UTC-4 ………………………Step-4

Let us understand how the same person who was in London can catch the airbus/flight which was scheduled at same time, same date at three different locations say at Hyderabad ,Dubai ,Canada and reach back Home(London) .

Person traveling from London to Hyderabad

time travel -distance from London to Hyderabad

For London is UTC+1 ………………………….Step-1

For Hyderabad is UTC+5:30 …………..Step-2

From step-1 and step-2,we can understand that Hyderabad is 4 hr:30 mins ahead of London.

So the person who was in London should travel ahead of time in-order to catch bus/fight at the scheduled date and time in Hyderabad.

Average aerial distance from London to Hyderabad =7717 km

Speed =Distance/time=7717/(5.5-1)=7717/4.5=1714.8 km/hr

Assuming that that person have Sukhoi Su-30MKI fighter jet in which he can travel from London to Hyderabad and the flight/air bus which that person should catch is also Sukhoi Su-30MKI fighter jet which can move at the top speed of 2120 km/hr.

So the person with the fighter  jet should move ahead of time from London and move at the speed of 1714.8 km/hr to catch airbus/flight in Hyderabad which was scheduled at time 05:30,date:10.10.2020 …..Step-4

Person traveling from Hyderabad to Dubai

time travel-distance from Hyderabad to Dubai

For Hyderabad is UTC+5:30 …………..Step-2

For Dubai is UTC+4…………………………Step-3

From step-2 and step-3,we can understand that Dubai is 1 hr:30 mins behind of Hyderabad.

So the person who was in Hyderabad should travel back in time in-order to catch bus/fight at the scheduled date and time in Dubai.

Average aerial distance from Hyderabad to Dubai=2551 km

Speed =Distance/time=2551/(5.5-4)=2551/1.5=1700.6 km/hr

Assuming that that flight/air bus which that person should catch is Sukhoi Su-30MKI fighter jet which can move at the top speed of 2120 km/hr .

So the person with the fighter jet should move back in time from Hyderabad and move at the speed of 1700.6 km/hr to catch bus/flight in Dubai which was scheduled at time 05:30,date:10.10.2020 …..Step-5

Person traveling from Dubai to Canada

time travel-distance from Dubai to Canada

For Canada is UTC-4 ………………………Step-4

For Dubai is UTC+4…………………………Step-3

From step-3 and step-4,we can understand that Canada is 8 hr:00 mins behind of Dubai.

So the person who was in Dubai should travel back in time in-order to catch bus/fight at the scheduled date and time in Canada.

Average aerial distance from Dubai to Canada=10799 km

Speed =Distance/time=10799/(4+4)=10799/8=1349.8 km/hr

Assuming that that flight/air bus which that person should catch is Sukhoi Su-30MKI fighter jet which can move at the top speed of 2120 km/hr .

So the person with the fighter  jet should move back in time from Dubai and move at the speed of 1349.8 km/hr to catch bus/flight in Canada  which was scheduled at time 05:30,date:10.10.2020 …..Step-6

Person traveling from Canada to Home(London)

time travel-distance from Canada to London

For Canada is UTC-4 ………………………Step-4

For London is UTC+1 ………………………….Step-1

From step-1 and step-4,we can understand that Home(London) is 5 hr:00 mins ahead of Canada.

So the person who was in Canada should travel ahead of time in-order to reach Home (London)

Average aerial distance from Canada to Home(London)=6271 km

Speed =Distance/time=6271/(1+4)=6271/5=1254.2 km/hr

Assuming that that person have Sukhoi Su-30MKI fighter jet which can move at the top speed of 2120 km/hr.

So the person with the fighter  jet should move ahead of time from Canada and move at the speed of 1254.2 km/hr in order to reach Home(London)………………..Step-7

Answer to Question -1(time travel)

So from step-4,step-5,step-6 we can understand that same person with the help of Sukhoi Su-30MKI fighter jet moving at different speeds can able to catch airbus/flight which was scheduled at fixed time 05:30 and fixed date 10-10-2020.

So at fixed date & fixed time it is practically possible for same person to be at 3 different locations(Hyderabad,Dubai,Canada).

Answer to Question -2 (time travel)

So from step-4,step-5,step-6 ,step-7 we can understand that same person with the help of Sukhoi Su-30MKI fighter jet who was in London traveled ahead of time to reach Hyderabad , again traveled back in time to reach Dubai, again traveled back in time to reach Canada ,again traveled ahead of time to reach Home(i.e London)

So it is practically possible for a person to move ahead of time and to move back in time.

Answer to Question -3 (time travel)

So from step-4,step-5,step-6 ,step-7 the person who was in London traveled ahead of time to reach Hyderabad , again traveled back in time to reach Dubai, again traveled back in time to reach Canada ,again traveled ahead of time to reach Home(i.e London)

Assuming ahead in time as positive(+) and back in time as negative (-)

So the resultant travel/journey time from London-Hyderabad-Dubai-Canada-London(Home)

 = +4.5 hr – 1.5 hr – 8 hr + 5 hr =0 hr ————– 1

The Time and date when the person start the journey at London is UTC+1,10.10.2020 and the time and date when the person reached Home(London is also UTC+1,10:10:2020  ……………2

So from 1 & 2,it is practically possible for same person to move ahead of time and to move back in time and the resultant time during the journey from London-Hyderabad-Dubai-Canada-London(Home) is “Zero”  …………Case Study (1)

Comparison of Case study(1) time travel with ancient scriptures

So from Case study (1) time travel we can understand that same person can be at three different locations at fixed date and fixed time and travel time or Journey time between those locations is “Zero”.

The above case study(1) time travel is similar to story written in ancient Indian scripture where Lord Ganesh made three rounds around Lord Shiva and Goddess Parvati to complete the race/competition which was kept between Ganesh and Kartikeya to travel around the world.

So Lord Ganesh starting first round around Shiva,Parvati is like Case study 1 ,i.e starting the race in Kailash to travel with the help of mouse(his vehicle) which can move at top speed of 2120 km/hr or even more and by the time he complete third round, reached home(Kailash) and the travel or journey time is “Zero” and this may be the reason for the people of Kailash might seemed that Lord Ganesh just revolving around the Lord Shiva and Parvati.

This may be reason how Lord Ganesh might won the race/competition

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About ancientindiantech

The founder and author of this blog is Ashwini Kumar P. He is a graduate in Civil engineering from NIT Warangal.

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